Php/docs/function.pg-field-table

• PHP Manual
• PostgreSQL 函数
• Returns the name or oid of the tables field

pg_field_table

(PHP 5 >= 5.2.0, PHP 7)

pg_field_table — Returns the name or oid of the tables field

说明

pg_field_table ( resource $result , int $field_number [, bool $oid_only = false ] ) : mixed

pg_field_table() returns the name of the table that field belongs to, or the table's oid if oid_only is true.

参数

result

PostgreSQL query result resource, returned by pg_query(), pg_query_params() or pg_execute() (among others).

field_number

Field number, starting from 0.

oid_only

By default the tables name that field belongs to is returned but if oid_only is set to true, then the oid will instead be returned.

返回值

On success either the fields table name or oid. Or, false on failure.

范例

Example #1 Getting table information about a field

<?php$dbconn = pg_connect("dbname=publisher") or die("Could not connect");$res = pg_query($dbconn, "SELECT bar FROM foo");echo pg_field_table($res, 0);echo pg_field_table($res, 0, true);$res = pg_query($dbconn, "SELECT version()");var_dump(pg_field_table($res, 0));?>

以上例程的输出类似于：

foo
14379580

bool(false)

注释

Note:

Returning the oid is much faster than returning the table name because fetching the table name requires a query to the database system table.

参见

• pg_field_name() - 返回字段的名字
• pg_field_type() - 返回相应字段的类型名称